Question

Calculate the area of cross section of a wire of length 2m, its resistance is 25Ω and the resistivity of material of wire is 1.84*10-6 Ωm.
Jaldi batao

Answer 1

Answer:

Given –

• Length of the wire = 2 m.
• Resistance = 25 ohm.
• Resistivity of the material = 1.84 × 10^{-6} ohm m.

To Find –

• Area of cross section.

Solution –

Formula : Resistance = Resistivity* l/A

Hence, A = Resistivity * l/Resistance

➸ A = rho*l/R

Substituting the values,

➸ A = 1.84 × 10^{-6} * 2/25

➸ A = 1.84 × 10^{-6} * 1/12.5

➸ A = 184 × 10^{-6} × 10/125 × 100

➸ A = 184 × 10^{-6}/125 × 10

➸ A = 1.472 × 10^{-6}/10

➸ A = 1.472 × 10^{-6-1}

➸ A = 1.472 × 10^{-7} m²

Hence, Area of cross section of the wire is 1.472 × 10^{-7} m².

Answer 2

Answer:

184×10[-6]÷125×10.....