Question

Calculate the area of cross section of a wire of length 2m, its resistance is 25ohm and the resistivity of material wire is 1.84*10^-6ohmm.
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Answer 1

Answer

• Area of cross-section , A = 1.472 × 10⁻⁷ m²

Given

• A wire of length 2 m, having resistance of 25 ohm and the resistivity of material wire is 1.84*10⁻⁶ ohm-m

To Find

• Area of cross section , A

Formula

$\bf{\blue{R=\dfrac{\rho l}{A}}}$

where ,

• R denotes Resistance
• ρ denotes resistivity of the material
• l denotes length
• A denotes Area of cross-section

Solution

Resistance , R = 25 Ω

Length , l = 2 m

Resistivity , ρ = 1.84 × 10⁻⁶ Ω-m

Area of cross-section , A = ? m²

Now apply the formula

$\implies \tt R=\dfrac{\rho l}{A}\\\\\implies \tt A=\dfrac{\rho l}{R}\\\\\implies \tt A=\dfrac{1.84 \times 10^{-6} \times 2}{25}\\\\\implies \tt A=1.472 \times 10^{-7}$

Answer 2

Explanation:

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