Question

Calculate the area of cross section of a wire of length 2m, its resistance is 25Ω and the resistivity of material of wire is 1.84*10-6 Ωm.

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Answer 1

Given

• Length of material (L) = 2m
• Resistance of material (R) = 25 Ω
• Resistivity of material (ρ) = 1.84^10-6Ωm

To find

• Area of cross section of a wire of length

Solution

• $\Large{\underline{\boxed{\bf{R=\rho{\dfrac{L}{A}}}}}}$

• R = Resistance
• A = Area of cross section
• L = length
• ρ(rho) = Resistivity

$\tt{\underline{\red{According\:to\:given\:condition}}}$

• $\Large{\underline{\boxed{\bf{A=\rho{\dfrac{L}{R}}}}}}$

$\tt{\underline{\purple{Put\:the\:value\:of\:R,\:L,\:\rho}}}$

$\implies\sf A={1.84\times{10^{-6}}\times\dfrac{2}{25}}$

$\implies\sf A={1.84\times{10^{-6}}\times\dfrac{2}{25}}$

$\implies\sf A={3.68\times{10^{-6}}\times\dfrac{1}{25}}$

$\implies\sf A={0.1472\times{10^{-6}}}m^2$

$\implies\sf A={1.472\times{10^{-7}}}m^2$

Hence,

$\sf{\underline{\red{Area\:of\:cross\:section\:of\:material\:is\:1.472\times{ 10^{-6}}m^2}}}$

Answer 2

Question:-

Calculate the area of cross section of a wire of length 2m, its resistance is 25Ω and the resistivity of material of wire is 1.84*10-6 Ωm.

To Find:-

• Find the area of cross section.

Given:-

• Length of material = 2m

• Resistance of material = 25 Ω

• Resistivity of material = 1.84^10-6 Ωm

Solution:-️

➭ R = pl/A️

➭ A = pl/R️

➭ A = 1.84 × 10−⁶ × 2 25️

➭ A = 1.472×10−⁷m²

∴ Area of cross section = 1.472×10−⁷m²