Math, asked by Krishajodhani, 16 hours ago

Calculate the area of each of these shapes


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Answers

Answered by Hadystai
1

Answer:

a)  Semicircle's area

  • \frac{1}{2} (\pi . radius^{2} )
  • = \frac{1}{2} x \frac{22}{7} x 8 x 8
  • = \frac{704}{7}
  • = 100. 571 sq.cm

b) 1/4th of circle or quadrant

  •  \frac{\pi r^{2} }{4}
  • = \frac{1}{4} x \frac{22}{7} x 10 x 10
  • = \frac{550}{7}
  • = 78 .571 sq.cm

c) A part of a circle

  • 360/30 = 12
  • Area = \frac{\pi r^{2} }{12}
  • = \frac{22 X 15 X 15}{12 X  7}
  • = \frac{4950}{84}
  • = 58.928 sq.cm

d) Area of figure =  Semicircle + Rectangle

  • ( \frac{6 X 6 X 22}{2 X 7} )+ ( 8 x 6)
  • = 56.571 + 48
  • = 104.571 sq.cm

e) Area of three-sided concave figure

  • Suppose the hypotenuse is  part of circle A and figure part of square B
  • Circle A of radius r contains 90° arc (hypotenuse)
  • Due to tangency, the other two sides form a right angle/
  • The area of the figure is the difference between the area of square B and the circular sector of circle A.
  • The area of a square B = 3^{2} = 9 sq.cm
  • The area of the sector is  90°/360°  (or 1/4) of the area of circle A, yielding  πr2/4 = \frac{22x3x3}{7x4} = 7.01
  • Area = 9 - 7.01 = 1.98 sq.cm

f) Area of the figure

  • Circle + 2 semicircles or 1 smaller circle
  • = \frac{22X3X3}{7} + \frac{22 X 1 X 1}{7}
  • =  28.28 + 3.14
  • = 31.42 sq.cm
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