Calculate the area of each of these shapes
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a) Semicircle's area
- = x x 8 x 8
- =
- = 100. 571 sq.cm
b) 1/4th of circle or quadrant
- = x x 10 x 10
- =
- = 78 .571 sq.cm
c) A part of a circle
- 360/30 = 12
- Area =
- =
- =
- = 58.928 sq.cm
d) Area of figure = Semicircle + Rectangle
- ( )+ ( 8 x 6)
- = 56.571 + 48
- = 104.571 sq.cm
e) Area of three-sided concave figure
- Suppose the hypotenuse is part of circle A and figure part of square B
- Circle A of radius r contains 90° arc (hypotenuse)
- Due to tangency, the other two sides form a right angle/
- The area of the figure is the difference between the area of square B and the circular sector of circle A.
- The area of a square B = = 9 sq.cm
- The area of the sector is 90°/360° (or 1/4) of the area of circle A, yielding πr2/4 = = 7.01
- Area = 9 - 7.01 = 1.98 sq.cm
f) Area of the figure
- Circle + 2 semicircles or 1 smaller circle
- = +
- = 28.28 + 3.14
- = 31.42 sq.cm
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