Question

calculate the area of quadrilateral ABCD
calculate the area of trapezium PQRS

Answer 1

For Quadrilateral ABCD:
In triangle DBC,
${bc}^{2} + {bd}^{2} = {dc}^{2}$
${bd}^{2} = {17}^{2} - {8}^{2} \\ bd = 15cm$
In triangle ABD,
${ad}^{2} + {ab}^{2} = {bd}^{2}$
${ab}^{2} = {15}^{2} - {9}^{2} \\ ab = 12cm$
Now just apply 1/2base×height
Area of triangle ABD,
1/2 ×9×12=54cm^{2}
Area of second triangle,
1/2×15×8=60cm^{2}
Add both areas,
Area of the Quad.=114cm^2

Now for trapezium,
Apply pythagoras theorem in Triangle RTQ to find RT=15cm

Then Apply area of trapezium=1/2(sum of parallel sides)×height
Area of the trapezium=180cm^2

Answer 2

Answer:

This is your answer okkkkkkkkkk