Question

calculate the area of quadrilateral ABCD in which angle A = 90 AB = 16 AD = 12 and BC=CD= 12.5​

Answer 1

Step-by-step explanation:

Let<A be 90

Construction --- Join diagonal BE

solution

Triangle ABD

<A=90

BY Pythagorus theorem

(BD)^2=(AD)^2 + (AB)^2

(BD)^2=(12)^2 + (16)^2

(BD)^2=144 + 256

(BD)^2=400

BD= 20