Calculate the area of quadrilateral ABCD in which ∆ BCD is equilateral triangle with each side equal to 26 CM, angle BAD = 90° and AD = 24 cm
Answers
GIVEN :
• ANGLE BCD IS EQUILATERAL TRIANGLE
• EACH SIDE = 26 CM
• ANGLE BAD = 90°
• AD = 24 CM
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TO FIND :
=> The area of quadrilateral ABCD = ?
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Step - by - step explaination :
In ∆ ABD,
Area of quadrilateral ABCD = area of ∆DAB + area of ∆DCB
Area of quadrilateral ABCD = 412.32cm²
Step-by-step explanation:
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Question:-
Calculate the area of quadrilateral ABCD in which ∆ BCD is equilateral triangle with each side equal to 26 CM, angle BAD = 90° and AD = 24 cm.
Answer:-
The area of quadrilateral ABCD is 412.76 cm²
Step-by-step explanation:
Step 1 : Quadrilateral ABCD forms two triangles.
Equilateral triangle BCD with sides 26 cm and right angled triangle BAD with base 24 cm and hypotenuse 26 cm.
Step 2 : Using Pythagoras theorem get the height AB of the right angled triangle and the height of the Equilateral triangle.
AB = Square root of (BD² - AD²)
= Square root of (676 - 576)
= square root of 100 = 10 cm
Height of the Equilateral triangle :
Height = square root of (26² - (26/2)²)
= Square root of (507) = 22.52 cm
Step 3 : Calculate the area of the two triangles.
Area of a triangle = ½b × h
Area of the right angled triangle = ½ × 24 × 10 = 120 cm²
Area of the Equilateral triangle = ½ × 26 × 22.52 = 292.76 cm²
Step 4 : Sum the two areas to get the total area which is the area of quadrilateral ABCD.
292.76cm² + 120 cm² = 412.76 cm²