Question

calculate the area of rectangle whose length is (3x+5) and breadth is (2y+4)?

Answer 1

Answer:

2(l+b)

Step-by-step explanation:

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Answer 2

Answer:

$\red\bigstar$ Area of the rectangle =  (6xy +12x + 10y + 20) units.

SOLUTION

Length of the rectangle = (3x+5)

Breadth of the rectangle = (2y+4)

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 3x+5 }\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 2y+4}\put(-0.5,-0.4){\bf }\put(-0.5,3.2){\bf }\put(5.3,-0.4){\bf }\put(5.3,3.2){\bf }\end{picture}$

Area of  a rectangle = l × b , Where l is the length and b is the breadth of the rectangle.

Here,

l = 3x+5

b = 2y+4

⇒ Area of the rectangle = (3x+5)(2y+4)

⇒ Area of the rectangle = (3x × 2y) + (3x × 4) + (5×2y) + (5 × 4)

⇒ Area of the rectangle = 6xy +12x + 10y + 20 .

∵ We are not given the unit of measurement of the rectangle , we can write it as unit.

∴ Area of the rectangle =  6xy +12x + 10y + 20 units.