Question

calculate the area of shaded region in the given figure where ABCD is square of side 16cm. Figure is given below Please answer it and please explain also....

Answer 1

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Answer 2

Answer:

area of the shaded region is 145.92 cm²

Step-by-step explanation:

refer to the image attached

side of square = 16 cm

ABQD forms a sector with radius 16cm and angle 90°

area of DBQ = Area of sector ABQD - Area of triangle ADB

area of sector = $\frac{\theta \ \pi \ r^{2} }{360}$

area of sector ABD = $\frac{90(3.14)16^{2} }{360}$

                           = 200.96 cm²

area of triangle ADB = $\frac{1(bh)}{2}$

                                     = $\frac{16*16}{2}$ = 128 cm²

area of shaded region DBQ = 200.96-128  = 72.96 cm²

area of shaded region DBQ = area of shaded region DBP

total area of the shaded region = 72.96×2

                                                     = 145.92 cm²

hence, area of the shaded region is 145.92 cm²