Calculate the area of shaded triangle.
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Required Answer:-
Given To Find:
- The area of the shaded region.
Solution:
Given that, (See the image)
→ OD = 3cm
→ OC = 6cm
Therefore,
→ CD = OD + OC
→ CD = 3cm + 6cm
→ CD = 9cm
→ ABCD is a rectangle.
→ AB = CD
→ AB = 9cm
→ Area of ABCD = AB × BC
→ Area of ABCD = 9 × 7 cm²
→ Area of ABCD = 63cm²
Area of ∆DOP,
= 1/2 × PD × OD
= 1/2 × 4 × 3 cm²
= 6cm²
→ Area of ∆DOP = 6cm²
Area of ∆BOC,
= 1/2 × OC × BC
= 1/2 × 6 × 7 cm²
= 21cm²
→ Area of ∆BOC = 21cm²
Area of ∆ABP,
= 1/2 × AB × AP
= 1/2 × CD × AP (∵ AB = CD)
= 1/2 × CD × (AD - PD)
= 1/2 × 9 × (7 - 4)
= 1/2 × 27
= 13.5cm²
→ Area of ∆ABP = 13.5cm²
Therefore, area of shaded region,
= Area of rectangle - Area of three triangles
= 63 - (6 + 21 + 13.5) cm²
= 63 - 40.5cm²
= 22.5cm²
→ So, the area of the shaded region is 22.5cm²
Note the formula used:
- Area of a rectangle = Length × Breadth.
- Area of a triangle = 1/2 × Base × Height.
Answer:
- The area of the shaded region is 22.5cm²
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