Question

Calculate the area of the designed region common between the two quadrants of circles of radius 8 cm each. ( figure given in attachment)




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Answer 1

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Answer 2

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Step-by-step explanation:

ANSWER

Area of shaded region =2× Area of segment BD

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD=

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 =

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 4

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD =

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 2

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD =50.24−32=18.24cm

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD =50.24−32=18.24cm 2

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD =50.24−32=18.24cm 2

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD =50.24−32=18.24cm 2 ∴ Area of shaded region =2×18.24=36.48cm

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,Area of quadrant ABD= 4π×r 2 = 41 ×3.14×8×8=50.24cm 2 Area of △ABD = 21 ×8×8=32cm 2 ∴ Area of segment BD = Area of quadrant ABD − Area of △ABD =50.24−32=18.24cm 2 ∴ Area of shaded region =2×18.24=36.48cm 2