Question

calculate the area of the designed region in Fig. 12.34 common between the two quadrants of circles of radius 8 cm each. ​

Answer 1

Step-by-step explanation:

HEY MATE ..

ANSWER

Area of shaded region =2× Area of segment BDConsidering the quadrant ABD,

⇒Area of quadrant ABD = π × r^2/4= 1/4 ×3.14×8×8=50.24 cm^2.

⇒Area of ∆ABD = 1/2 ×8×8 = 32 cm^2 .

∴ Area of segment BD = Area of quadrant ABD − Area of △ABD =50.24−32=18.24cm ^2

∴ Area of shaded region =2×18.24=36.48cm ^2

Answer 2

$\huge\mathcal\colorbox{black}{{\color{yellow}{ANSWER☆~~~}}}$

AB = BC = CD = AD = 8 cm

Area of ΔABC = Area of ΔADC = (½)×8×8 = 32 cm2

Area of quadrant AECB = Area of quadrant AFCD = (¼)×22/7×82

= 352/7 cm2

Area of shaded region = (Area of quadrant AECB – Area of ΔABC) = (Area of quadrant AFCD – Area of ΔADC)

= (352/7 -32)+(352/7- 32) cm2

= 2×(352/7-32) cm2

= 256/7 cm2