Calculate the area of the designed region in figure, common between the two quadrants of the circles of radius 10 cm each. (use n = 3.14)
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Area of DBC=2πr2=25π
Area of DBC=2πr2=25πarea of ABD=2πr2=25π
Area of DBC=2πr2=25πarea of ABD=2πr2=25π∴ area of designed region =50π−100
=50×3.14−100
=50×3.14−100 =2314−100
=57 cm2
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