Question

Calculate the area of the quadrilateral ABCD from the
measurements given in figure.​

Answer 1

Answer:

answer

Step-by-step explanation:

that is 45cm hope it will help you

Answer 2

Answer:

► GIVEN :↝

• ABCD is a quadrilateral and measurement of sides are -
• AB = 12 cm
• AD = 4 cm
• BD = 16 cm
• CE = 3 cm

► SOLUTION :↝

We haven't any formula to solve it directly so we should separate it in two figure( Triangle)

In △ BAD and △BCD

Taking the first triangle.

△ BAD

AB is the base and AD is the height of triangle.

AB = 12 cm

AD= 4 cm

$\sf \: Area \: of \: \triangle = \frac{1}{2}(base)(height)$

$\sf \: Area \: of \: △ \: ABD = \frac{1}{2} \times (12) \times (4)$

$\sf \: Area \: of \: △ \: ABD = 24 \: {cm}^{2}$

Taking the second triangle .

△ BCD

Where BD is base and CE is the height of triangle

BD = 16 cm

CE = 3 cm

Again

$\sf \: Area \: of \: \triangle = \frac{1}{2}(base)(height)$

$\sf \: Area \: of \: △ \: BCD= \frac{1}{2} \times (16) \times (3)$

$\sf \: Area \: of \: △ \: ABD = 24\: {cm}^{2}$

$\sf \: Now \: \: Area \: \: of \: \: quadrilateral \: \: = \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf Area \: of \: △BAD + Area \: of \: △ BCD</p><p>$

$\sf \: Now \: \: Area \: \: of \: quadrilateral \: \: = 24 + 24 \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 48 \: {cm}^{2}$