Question

Calculate the area of the quadrilateral ABCD in which
AB = BD = AD = 10 cm, angel BCD =90° and CD=8 cm.
(Take √3 = 1.732).​

Answer 1

Answer:

Step-by-step explanation:

area of abd

\frac{ \sqrt{3} }{4} \times {10}^{2}

\frac{1.732}{4} \times 100

=43.3

{cm}^{2}

for finding BC we can use Pythagoras thm

{10}^{2} - {8}^{2} = {bc}^{2}

\sqrt{36} = 6

now area of another triangle

\frac{1}{2} \times 8 \times 6

24

total area =67.3

Answer 2

Answer:

Hope it helps you.....