Question

calculate the area of the quadrilateral ABCD in which AB=BD=AD=10cm,angle BCD=90° and CD=8cm.​

Answer 1

Area of quadrilateral ABCD=

Area of triangle ABD+Area of triangle BCD

Area of equilateral triangle ABD=(√3/4)a²

(√3/4)10²

√3*25=25√3 cm²

Area of triangle BCD

BC=10²-8²

=100-64=36

So, BC=√36=6cm

Area=(1/2)bh

=(1/2)6*8

=24cm²

Total area=25√3cm²+24cm²

=49√3cm²

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