Question

Calculate the area of the regular pentagon below:


A regular pentagon with side length of 11.8 inches and dotted line from center to middle of side of 8.1 inches.

Answer 1

Answer:

Area of regular pentagon is 238.95 square inches.

Step-by-step explanation:

Given a regular pentagon with side length of 11.8 inches and dotted line from center to middle of side of 8.1 inches.

we know a regular polygon divides into 5 congruent triangles.

Side of pentagon i.e base of one triangle is 11.8 inches.

Also, distance from center to middle of side which is height of triangle is 8.1 inches.

Area of 1 triangle= \frac{1}{2}\times base\times height

2

1

×base×height

= \frac{1}{2}\times 11.8\times 8.1

2

1

×11.8×8.1

= 47.79 sq inches.

Area of regular pentagon=area of 5 congruent triangles= 5\times 47.795×47.79 =238.95 sq inches

Answer 2

Answer:

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Step-by-step explanation:

Area of regular pentagon is 238.95 square inches.

Step-by-step explanation:

Given a regular pentagon with side length of 11.8 inches and dotted line from center to middle of side of 8.1 inches.

we know a regular polygon divides into 5 congruent triangles.

Side of pentagon i.e base of one triangle is 11.8 inches.

Also, distance from center to middle of side which is height of triangle is 8.1 inches.

Area of 1 triangle= \frac{1}{2}\times base\times height

2

1

×base×height

= \frac{1}{2}\times 11.8\times 8.1

2

1

×11.8×8.1

= 47.79 sq inches.

Area of regular pentagon=area of 5 congruent triangles= 5\times 47.795×47.79 =238.95 sq inches