Question

Calculate the area of the shaded region.

Answer 1

Step-by-step explanation:

PQR is an Isosceles triangle so PE bisects QR

QE = ER

In ∆PQE => QE² = PQ² - PE² = 7² - PE²

In ∆PDE , DE² = PD² - PE² = 5² - PE²

Now,

QD × DR = (QE + DE) (QE - DE)

=> QD × DR = ( QE)²- ( DE)²

=> QD × DR = 7² -5² = 24

So they can only be 3 × 8 or 4 × 6.

Hence 3+8 = 11,

4+6 =10