calculate the area of the trapezium given below
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in Triangle DAB, by applying Pythagoras theorem=41^2-40^2=81..so DA=√81=9cm..so area of trapezium=1/2*(20+40)*9=30*9=270cm^2
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(AD)^2=(DB)^2-(AB)^2
= (41)^2-(40)^2
=81 cm AD=9
Area= 1/2*(40+20)*9
=270 sq cm
Area= 1/2*(sum of parallel lines)*distance between them
= (41)^2-(40)^2
=81 cm AD=9
Area= 1/2*(40+20)*9
=270 sq cm
Area= 1/2*(sum of parallel lines)*distance between them
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