Calculate the area of the triangle for which two of its sides are given by the vectors A = 5i - 3j, B = 4i + 6j.
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Given conditions ⇒
Vector A = 5i - 3j
Vector B = 4i + 6j
Let us find the Cross-products of these vectors,
(5i - 3j + 0k) × (4i + 6j + 0k) = (0i + 0k + 48k)
Using the Formula of the Area of the Triangle when two consecutive sides in vector forms is given.
∴ Area of the Δ = 1/2[A + B]
= 1/2[0i + 0j + 48k]
= 1/2( )
= 1/2()
= 48/2
= 21 unit²
Hence, the area of the triangle is 21 unit².
Hope it helps.
Vector A = 5i - 3j
Vector B = 4i + 6j
Let us find the Cross-products of these vectors,
(5i - 3j + 0k) × (4i + 6j + 0k) = (0i + 0k + 48k)
Using the Formula of the Area of the Triangle when two consecutive sides in vector forms is given.
∴ Area of the Δ = 1/2[A + B]
= 1/2[0i + 0j + 48k]
= 1/2( )
= 1/2()
= 48/2
= 21 unit²
Hence, the area of the triangle is 21 unit².
Hope it helps.
Mgram1976:
if cross multiplication how 48kvector come
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