Question

calculate the area of the triangle whose sides are 18cm,24cm and 30cm in length. find the length of the altitude corresponding to the smallest side.

Answer 1

here is ur ans hope it helps u

Answer 2

STEP 1: Find P:

$\text {P = } \dfrac{a+ b+ c}{2}$

$\text{P} = \dfrac{18 + 24 + 30}{2} = 36$

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STEP 2: Find area:

$\text{Area of triangle = } \sqrt{p(p-a)(p-b)(p-c)}$

$\text{Area of triangle = } \sqrt{36(36-18)(36-24)(36-30)}$

$\text{Area of triangle = } \sqrt{46656}$

$\textbf {Area of triangle = 216 units}^2$

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STEP 3: Find the length of the altitude corresponding to the smallest side:

Area = 1/2 base x height

216 = 1/2 (18) x height

216 = 9 x height

height = 216 ÷ 9

height = 24 cm

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Answer: The length of the altitude is 24 cm