calculate the area of the triangle whose vertices are (1 4)(4.-3) and (-9,7)
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Given (1,−1),(−4,6),(−3,−5)
Let us Assume A(x1,y1)=(1,−1)
Let us Assume B(x2,y2)=(−4,6)
Let us Assume C(x3,y3)=(−3,−5)
Area of triangle
=21[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
Now, Area of given triangle
=21[{1(6−(−5))}+(−4){(−5+1)−3(−1−6)}]
=21{30+16+21}
=267 Square units
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