Calculate the area of trapezium as shown in the figure:
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can you please send me the formula of area of trapezium
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DA IS PARALLEL TO CQ
THEREFORE, CB×CB =CO×CO+OB×OB
17×17=CO×CO+8×8
289=64+CO×CO
CO×CO=289-64
CO =15 CM
AREA OF RECTANGLE DCOA=AO×CO
(6×15) CM
90CM
AREA OF TRIANGLE COB =√S(S-A) (S-B) ( S-C)
S=A+B+C/2
S=36CM
√36(36-17) (36-15) (36-8)
316cm
BOTH AREA SUM =AREA OF TRAPEZIUM
(90+ 316) CM
406CM APPROXIMATELY
PLEASE MAKE ME AS BRAINLIEST.
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