Question

calculate the area of trapezium as shown in the figure

Answer 1

Answer:

DC=6

AB=6+8=14

IN ΔCOB

BY PYTHAGORUS THEOREM

OC²=BC²-OB²

      =17²-8²

       =289-64

      =225

∴OC=√225=15

AREA OF TRAPEZIUM=DC+AO/2(OC)

                                     =6+6/2(15)

                                     =6*15

                                     =90 cm²

Answer 2

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$height = \sqrt{( {17})^{2} - {(8)}^{2} } \\ \\ = \sqrt{289 - 64} \\ \\ = \sqrt{225} \\ \\ = 15 \\ \\ \purple{area \: of \: trapezium} \\ \red{ = \frac{1}{2} \textbf{(sum \: of \: opposite \: sides) * height}} \\ \\ \red {\textbf{ {1}/{2}*18 *15}} = \green{ \boxed{ \boxed{ \boxed {\boxed{ \boxed{135cm^2}}}}}}$

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