Question

calculate the area of trapezium pqrs in the given figure​

Answer 1

Answer:

124

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Answer 2

Answer:

$rt \: = \sqrt{ {17}^{2} - {8}^{2} }$

$= \sqrt{289 - 64}$

$= \sqrt{225}$

$= 15$

PQ= 8+6+8

= 22

Area= PSRQ=

$\frac{1}{2} \times (6 + 22) \times 15$

$= \frac{1}{2} \times 28 \times 15$

$= 2 \times 14 \times 15$

$= 210 \: {cm}^{2}$