Question

Calculate the area of triangular field whose sides are 91 m, 98 m and 105 m. Find the height corresponding to the longest side.

Answer 1

This is simple if you know Heron's formula:

[tex]Area= \sqrt{s(s-a)(s-b)(s-c)}, where, s=semi perimeter; a,b,c are the sides.[/tex]

So, semi perimeter=(91+98+105)/2=147

Area=$\sqrt{147(56)(49)(42)}$

Area=4116$m^{2}$

So, height corresponding to largest side=4116/105=39.2m

I may have made some calculation errors, but you get the idea.