calculate the atom city of following molecule. 1. O3H2SO4, C2H2O4, 2H2O,(Al2SO4)3.
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!! Hey Mate !!
your answer is --
Firstly, it is necessary to know that what is atomicity ?
Ans => the number of atoms present in the molecules of an element is called atomicity .
1. O3H2SO4 => 3+2+1+4 = 10
So, atomicity of O3H2SO4 is 9
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2. C2H2O4 => 2+2+4 = 8
so, atomicity of C2H2O4 is 8
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3. 2H2O = 4+2 = 6
so, atomicity of 2H2O is 6
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4. (Al2SO4)3 = 2×3+1×3+4×3 = 6+3+12=21
so, atomicity of (Al2SO4)3 is 21.
________________________
【 Hope it helps you 】
your answer is --
Firstly, it is necessary to know that what is atomicity ?
Ans => the number of atoms present in the molecules of an element is called atomicity .
1. O3H2SO4 => 3+2+1+4 = 10
So, atomicity of O3H2SO4 is 9
----------------------
2. C2H2O4 => 2+2+4 = 8
so, atomicity of C2H2O4 is 8
----------------------
3. 2H2O = 4+2 = 6
so, atomicity of 2H2O is 6
----------------------
4. (Al2SO4)3 = 2×3+1×3+4×3 = 6+3+12=21
so, atomicity of (Al2SO4)3 is 21.
________________________
【 Hope it helps you 】
Anonymous:
delhi
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