calculate the atomic number and atomic
mass of an atom containing 19 electrons
and 20 neutrons. What should be its
electrochemical nature ? Answer with reason
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Answer:
Atomic no. = No. of electrons = 19
Atomic mass = No. of electrons + No. of neutrons = 19 + 20 = 49
Electronic configuration = 2, 8, 8, 1
It is electropositive as 1 electron is present in the valence shell
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