Question

calculate the atomicity of chlorine if 35.5g of it occupies 11200cm^3 at STP
please answer fast​

Answer 1

Answer:

1 mole of a gas occupies 22.4 L at STP, so Molar Mass that is, mass of 1 mole of chlorine gas equals to 35.5 g.

According to the fact,

volume of gas at STP = Number of moles * 22.4

or, 22.4 L = n * 22.4

or, n = 1

Thus from this it is coming out to be 1.

(Note: As per the data given, the atomicity of chlorine is coming out to be 1. However, chlorine is actually a diatomic molecule.)

hope you will be helpfull with this

Answer 2

Answer:

1mole of substance= 1g molecular mass of it and occupies 22400 cm³ ot S.T.P.

1 mole of chlorine= 1g mol. mass of chlorine and occupies 22400 cm³ at S.T.P.

Given:

1gm atom of chlorine occupies 11200 cm³.

$= \frac{22400 \times 35.5}{11200} = 71$

therefore the GMM =71g

therefore Atomicity = 71/35.5 = 2

therefore Atomicity of chlorine =2

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