Question

calculate the atoms of each constituent in 50g of CaCO3​

Answer 1

Answer:

How many atoms of each constituent element are present in 50 g of CaCO_(3) ? 50.0 grams of CaCO3=50.0100.0=0.5 gram mol. 0.5 gram mole of CaCO3 contain oxygen atoms =0.5×3×6.022×1023=9.03×1023 atoms. An element crystallizes in f.c.c. lattice with edge length of 400 pm.

Answer 2

gram molecular mass of CaCO3= 40+12+3×16=100g

<br>100.0 grams of CaCO3 is 1

gram mol <br> 50.0 grams of CaCO3 = 50.0/100.0= 0.5

one gram mole of CaCO3 contain Ca atom = 6.022×10^23

0.5 gram mole 9f CaCO3 contain Ca atom=

6.022×10^23×0.5= 3.01×10^23

one gram mole of CaCO3 contain Carbon atom = 6.022×10^23

0.5 gram mole of CaCO3 contain carbon atom= 3.01×10^23

one gram mole of CaCO3 contain oxygen atom= 3×6.022×10^23

0.5 gram mole of CaCO3 contain oxygen atom= 0.5× 3×6.022×10^23=9.03×10^23 atom