Calculate the available void present in bcc structure
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The total number of octahedral voids will be n and the total number of tetrahedral voids will be 2n, where n is the number of atoms in the lattice. So, bcc has 2 atoms, then the number of octahedral voids will be 2 and the total number of tetrahedral voids will be = 2 x 2 = 4.
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If number of molecules in a unit cell is N , then this unit cell will have N octahedral and 2N tetrahedral voids
face centered (fcc) / cubical closed packing (ccp) : N = 4
body centered cubic (bcc) : N = 2
simple cubic : N = 1
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