calculate the average atomic mass of silver. which exists naturally mixture of two isotopes 107 Ag47 (57%) and 109 Ag47 (43%)
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As we know, for bcc lattice,
r=
4
3
a
= 4 3
×0.8
=0.3463 nm
r=34×10
−2nm
By comparing, r=34×10
−x
=34×10
−2
nm
We get, x=2
Hence, the correct answer is 2.
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