Question

Calculate the average internal energy of a diatomic molecule at 300 k using law of equipartition of energy

Answer 1

hope this helps u in understanding

Answer 2

The average internal energy of a diatomic molecule is  1.035 × 10⁻²⁰ J.

We have to find the average internal energy of a diatomic molecule at 300K using law of equipartition of energy.

Law of equipartition of energy :

• It states that for any dynamic system in thermal equilibrium, the total energy for the system is equally divided among the degree of freedom.
• The average kinetic energy per degree of freedom is given by, KE = 1/2 KbT.
• average internal energy of a molecule using law of equipartition of energy is given by, E = N × 1/2 KbT., where N is degree of freedom of the molecule.

Here We have to find the average energy of diatomic molecule.

degree of freedom of a diatomic molecule , N = 5

∴ Average internal energy = 5 × 1/2 KbT

= 5 × 1/2 × 1.38 × 10⁻²³ J/K × 300 K

= 1.035 × 10⁻²⁰ J

Therefore the average internal energy of a diatomic molecule is  1.035 × 10⁻²⁰ J.

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