calculate the average kinetic energy of 0.8g methane at 27degree celcius
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Total kinetic energy = KE = 3/2*nRT
where n = Number of moles of the gas
R = Gas constant =8.314J/K/mole
T = Absolute temperature =273K
Molecular weight of methane = CH4
C = 12, H =1*4
12+4 = 16
Number of moles in 8.0 gm of methane
= 8.0/16.0 = 0.5
R = 8.314 joules/K/mole
T = 27 + 273 = 300 K
Total kinetic energy of the molecules in 8.0 gm of methane at 27 degree Celsius
According to formula:
= 0.5 * 3/2 * 8.314 * 300 = 1870.65 joules
Average kinetic energy = 1870.65/6.023 *10 23 *0.5
= 6.21 * 10 -21 joules/molecule Ans.
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