Question

calculate the average kinetic energy of hydrogen molecule at 0 degree C givenkB 1.38*10 -23jk-1

Answer 1

I hope that help you

Answer 2

Given :

Boltzmann's constant , $K_b=1.38\times 10^{-23}\ J/K$ .

Temperature of system , $T=0^oC=273 \ K$ .

To Find :

The average kinetic energy of hydrogen molecule .

Solution :

We know , average kinetic energy is given :

$K.E_{avg}=\dfrac{3}{2}K_bT\\\\K.E_{avg}=1.5\times1.38\times 10^{-23}\times 273\\\\K.E_{avg}=5.65\times 10^{-21}\ J$

Hence , this is the required solution .

Learn More :

Thermodynamics

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