Calculate the average velocity of the particle whose position vector changes from r₁ = 5i + 6j to r₂ = 2i + 3j in a time 5 second.
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Answer:
initial position (r1) = 5i+6j
final position (r2) = 2i+3j
change in position (r) = r2 -r1
= 2i+3j-5i-6j
= -3i-3j = 3√2 units (of length)
time(t) = 5s
average velocity =r/t
=3√2/5
=0.6√2
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