calculate the binding energy of Alpha particle in ergs.given masses of proton, neutron,helium nucleus is 1.00758, 1.00897, 4.00820 amu respectively.
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Given :
masses of proton=1.00758amu
mass of neutron=1.00897amu
mass of helium nucleus =4.00820 amu
Mass of Nucleus =mass of 2 protons +mass of 2 neutrons
=2(1.00758+1.00897)
=2x2.01655
=4.0331 amu
mass defect=4.0331-4.00820=0.0249amu
Binding Energy=mass defect x 931mev=0.0249x931=23.18Mev
[since 1amu=931 MeV]
Binding energy =0.00003713ergs
[since 1erg=624,145.70 Mev]
masses of proton=1.00758amu
mass of neutron=1.00897amu
mass of helium nucleus =4.00820 amu
Mass of Nucleus =mass of 2 protons +mass of 2 neutrons
=2(1.00758+1.00897)
=2x2.01655
=4.0331 amu
mass defect=4.0331-4.00820=0.0249amu
Binding Energy=mass defect x 931mev=0.0249x931=23.18Mev
[since 1amu=931 MeV]
Binding energy =0.00003713ergs
[since 1erg=624,145.70 Mev]
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