Question

Calculate the binding energy of n=4 of Be^3+

Answer 1

Answer

  Binding Energy = mass defect x

B per nucleus = ΔΔm × c2 × 931 MeV

B per nucleus = 0.06248 × 931.5 = 58.20 MeV

Number of nucleons in 9Be4 = 9

B per nucleon = 58.20958.209 MeV = 6.47 MeV

Answer 2

Explanation: Binding Energy = mass defect x  

B per nucleus = ΔΔm × c2 × 931 MeV

B per nucleus = 0.06248 × 931.5 = 58.20 MeV

Number of nucleons in 9Be4 = 9

B per nucleon = 58.20958.209 MeV = 6.47 MeV