Question

calculate the binding energy per nucleon in (MeV) of lithium nucleus,mass of proton=1.007830,mass of neutron=1.008670,mass of Li nucleus=7.016530​

Answer 1

Answer:

The mass defect of nucleus is Δm=(Zm

p

+Zm

n

−massofnucleus)

Δm=7[1.00759+1.300898]−14=0.11500a.m.u

The energy equivalent of this mass is E=107.98MeV

Therefore the binding energy per nucleon is 7.713MeV