Question

calculate the boiling point of a 0.01 molal soln of urea in water ( kb for water is 0.52 K kg mol^-1 )​

Answer 1

Answer:

Delta Tb = kb* m

= 0.52* 0.01

= 0.0052k

Delta Tb = T(urea sol) - T (water)

0.0052= T(urea) - 373k

T (urea) = 0.0052+373

=373.0052 K

Explanation:

bp of water = 100

so 100 +273 = 373