Question

Calculate the boiling point of a solution containing 0.61g of Benzoic acid in 50g of CS2 assuming 84% dissociation of acid. The boiling point of CS2 is 42.60C and Kb is 2.3 K/molal.​

Answer 1

b.pt - 42.60 = i x 2.3 x (0.61/122 x 1000/50)

b.pt - 42.60 = i x 2.3 x 0.1

b.pt - 42.60 = i x 0.23

here, i = 1 + (2-1)0.84

           = 1 + 0.84

           = 1.84

b.pt - 42.60 = 1.84 x 0.23

b.pt - 42.60 = 0.4232

b.pt = 43.0232C