Question

Calculate the boiling point of a solution containing 1.8g of non-volatile solute
(molar mass = 58g mol-¹) dissolved in 90g of benzene. [The boiling point of
pure benzene is 353.23K and K for benzene = 2.53K kg mol-¹​

Answer 1

Answer:

Explanation:

Answer :

354.102 K

Solution :

WB=1.8g,WA=90g=0.09kg,T∘b=353.23K

Kb=2.053 K kg mol−1,MB=58g mol−1,Tb=?

ΔTb=Kb×WBΔTb×WA=(2.53 K kg mol−1)×(1.8g)(58 g mol−1)×(0.09kg)=0.872K

Tb=T∘b+ΔTb=353.23+0.872=354.102K.