Question

calculate the boiling point of a solution containing zero point four five six grams of camphor dissolved in thirty one point four grams of acetone. if the molecular elevation constant per hundred grams of acetone is seventeen point two. ​

Answer 1

The boiling point of a solution 56.46 °C.

here is the explaination of this question......:

Given,

Kb per 100 gm of acetone = 17.2 degree C

Therefore,

Kb per 1000 gm of acetone = 1.72 degree C

We know,

Substituting the values,

Therefore, boiling point of solution = 56.30 + 0.16

 = 56.46 degree C