Question

CALCULATE THE BOILING POINT OF SOLN PREPARED BY ADDING 15 G GM OF NACL TO 250 GM OF WATER KBIS 0.5

Answer 1

Answer:

Mass of solute (NaCl), Wb = 15 g

Mass of solvent (water), Wa = 250 g

Molar mass of NaCl, Mb = 58.44 g/mol

Kb for water = 0.512 K kg/mol

we have to calculate the boiling point of solution, Tb = ?

we know that boiling point of pure water, Tb° = 373 K

because,

∆Tb = Kb * m

∆Tb = Kb * Wb * 1000

Wa * Mb

= 0.512 * 15 * 1000

58.44 * 250

=> ∆Tb = 0.53 K

Now,

∆Tb = Tb - Tb°

Tb = Tb° + ∆Tb

= 373 + 0.53

=> Tb = 373.53 K

Hence, boiling point of solution is 373.53 K

Hope it helps you ....