Question

Calculate the bond angle in h2o if dipole moment of h2o is 1.84 debye and dipole moment of oh bond is 1.5 debye

Answer 1

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μ=μ21+μ21+2μ1μ1cosα−−−−−−−−−−−−−−−−−√μ=μ12+μ12+2μ1μ1cos⁡α

In H2OH2O only two dipoles equal to μ1μ1 are operating due to two O−HO−H bonds.

Thus, 1.84=(1.5)2+(1.5)2+2(1.5)×(1.5)cosα−−−−−−−−−−−−−−−−−−−−−−−−−−−−√1.84=(1.5)2+(1.5)2+2(1.5)×(1.5)cos⁡α

cosα=−0.2476cos⁡α=−0.2476

α=140∘20′α=140∘20′

Hence C is the correct answer.

answered Apr 4, 2014 by meena.p