Calculate the bond length of C-X bond, if C-C bond length is 1.54 A, X-X bond length is 1 A and electronegativity values of C and X are 2 and 3 respectively
Answers
rc= dc-c/2 = 1.54/2 = 0.77
rx = dx-x/2 = 1.2/2 = 0.6
dc-x = rc + rx - 0.09(ex-ec)
= 0.77 + 0.6 - 0.09(3-2)
= 1.28 A*
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Answer:
The correct answer of this question is 1.18A
Explanation:
Given - The bond length of the C-X bond, if the C-C bond length is 1.54 A, X-X bond length is 1 A, and electronegativity values of C and X are 2 and 3.
To Find - Calculate the bond length of the C-X bond, if the C-C bond length is 1.54 A, X-X bond length is 1 A, and electronegativity values of C and X are 2 and 3 respectively.
Now, according to the question,
The bond length of X-X, M = 1A
The bond length of C-C, N = 1.54A
And, the radius of X-X bond, Rm = M/2 = 0.5A
Radius of C-C bond, Rn = N/2 = 0.77A
So, Bond length of C-X= Rm+Rn-0.09 ( 3-2 )=0.5 + 0.77 - 0.09 = 1.18A
Bond length of C - X is 1.18A
So, the bond length is 1.18A
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