Question

calculate the bond order of n2 n2+ and compare their stability

Answer 1

Bond order = No. of electron in bonding MOs
                  = (No.of electron in antibonding orbital/2)

 MO Conguration :
 N2( Total 14e-) =σ1s^2 σ*1s^2 σ2s^2 σ*2s^2 (π2px^2 =π2py^2 )σ2pz^2

 thus Bond order = 10-4/2 =6/2= 3

N2^+ (Total 13e-) =σ1s^2 σ*1s^2 σ2s^2 σ*2s^2 (π2px^2)=π2py^2)σ2pz^1
  
thus Bond order = 9-4/2=5/2= 2.5 


according the molecular orbital theory, N2 has more antibonding electrons than N2+. Also, more antibonding electrons lead to instability.
Thus N2+ is more stable than N2

i hope it will help you 
regards

Answer 2

Answer:

I

Explanation:

I hope it helps you.........