Question

Calculate the bond order of N2, O2, O+2, O-2, F2 and F2+ with ' suitable molecular orbital diagram'.

Answer 1

Concept Introduction: Bond Order is a part of Molecular Bonding in Compounds.

Given:

We have been Given: The bond order of N2, O2, O+2, O-2, F2.

To Find:

We have to Find: Calculate the bond order of N2, O2, O+2, O-2, F2.

Solution:

According to the problem, The formula of Bond Order is

$\frac{no. \: of \: electrons \: in \: bonding \: orbtal - no. \: of \: electrons \: in \: antibonding \: orbital}{2}$

therefore Bond Order of N2 is

$\frac{10 - 4}{2} = \frac{6}{2} = 3$

Bond Order of O2 is

$\frac{10 - 6}{2} = \frac{4}{2} = 2$

Bond Order of O+2 is

$\frac{9 - 4}{2} = \frac{5}{2} = 2.5$

Bond Order of O-2 is

$\frac{10 - 7}{2} = \frac{3}{2} = 1.5$

Bond Order of F2 is

$\frac{10 - 8}{2} = \frac{2}{2} = 1$

Final Answer: Bond Order of N2 is

$3$

Bond Order of O2 is

$2$

Bond Order of O+2 is

$2.5$

Bond Order of O-2 is

$1.5$

Bond Order of F2 is

$1$

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