Calculate the Brogiles wave lenght associated with an electron with velocity 1. 6×10^6m/s
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Answered by
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According to De-Broglie
Wavelength = Planck's constant / Momentum
So,
Wavelength = 6.626*10^-34 / (9.1*10^-31 kg)(6*10^6 m/s)
Planck's constant = 6.626*10^-34 Joules-second
Mass of an electron = 9.1*10^-31 kilograms
Therefore, i suppose wavelength can be calculated further.
Hope this helps you !
Wavelength = Planck's constant / Momentum
So,
Wavelength = 6.626*10^-34 / (9.1*10^-31 kg)(6*10^6 m/s)
Planck's constant = 6.626*10^-34 Joules-second
Mass of an electron = 9.1*10^-31 kilograms
Therefore, i suppose wavelength can be calculated further.
Hope this helps you !
Disly:
R u malu
Answered by
0
According to De-Broglie
Wavelength = Planck's constant / Momentum
So,
Wavelength = 6.626*10^-34 / (9.1*10^-31 kg)(6*10^6 m/s)
Planck's constant = 6.626*10^-34 Joules-second
Mass of an electron = 9.1*10^-31 kilograms
Therefore, i suppose wavelength can be calculated further.
this will be helpful 4 u
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