Calculate the buoyant force exerted by the liquid on the block in newton.
Answers
Answer:
The buoyant force on an object can be calculated using the Archimedes principle.
Explanation:
The buoyant force is a result of pressure exerted by the fluid. The fluid pushes on all sides of an immersed object, but as pressure increases with depth, the push is stronger on the bottom surface of the object than in the top (as seen in ).
You can calculate the buoyant force on an object by adding up the forces exerted on all of an object’s sides. For example, consider the object shown in.
The top surface has area
A
and is at depth
h1
; the pressure at that depth is:
P
1
=
h
1
ρ
g
,
where
ρ
is the density of the fluid and
g
≈
9.81
m
s
2
is the gravitational acceleration. The magnitude of the force on the top surface is:
F
1
=
P
1
A
=
h
1
ρ
g
A
.
This force points downwards. Similarly, the force on the bottom surface is:
F
2
=
P
2
A
=
h
2
ρ
g
A
and points upwards. Because it is cylindrical, the net force on the object’s sides is zero—the forces on different parts of the surface oppose each other and cancel exactly. Thus, the net upward force on the cylinder due to the fluid is:
F
B
=
F
2
−
F
1
=
ρ
g
A
(
h
2
−
h
1
)